How do I print the current date and time in bash?

Sample shell script to display the current date and time #!/bin/bash now=”$(date)” printf “Current date and time %s\n” “$now” now=”$(date +’%d/%m/%Y’)” printf “Current date in dd/mm/yyyy format %s\n” “$now” echo “Starting backup at $now, please wait…” # command to backup scripts goes here # …

Which command is used to write the system date in the MM DD YYYY format?

To format date in MM-YYYY format, use the command date +%m-%Y .

How do I print only the date in Linux?

1. Linux Syntax To Format Date For Display On Screen. The syntax is as follows for the GNU/date and BSD/date command:
2. Task: Display date in mm-dd-yy format. Open a terminal and type the following date command:
3. Task: Display time only.
4. How do I save time/date format to the shell variable?
5. A sample date session.
6. Conclusion.

How do I print a date in dd mm yyyy format in Unix?

To format date in DD-MM-YYYY format, use the command date +%d-%m-%Y or printf “%(%d-%m-%Y)T\n” $EPOCHSECONDS .

How do I create a date in bash?

To get the date in bash shell and add a date, you can use the GNU date command as date -d ‘Feb 12 +1 day’ +%F which will output 2020-02-13 .

What is date format DD MMM YYYY?

DD/MMM/YYYY. Two-digit day, separator, three-letter abbreviation of the month, separator, four-digit year (example: 25/JUL/2003) MMM/DD/YYYY. Three-letter abbreviation of the month, separator, two-digit day, separator, four-digit year (example: JUL/25/2003) YY/DDD.

How do I use printf in Bash?

The Bash printf builtin command support some date formats by using % (datefmt)T where datefmt is a format string passed to strftime and the corresponding argument is the Epoch time. Using printf makes the formatting to microseconds even simpler than when using the date command.

How do I format a date in Bash?

Bash Date format MM-DD-YYYY. To format date in MM-DD-YYYY format, use the command date +%m-%d-%Y or printf “%(%m-%d-%Y)T\ ” $EPOCHSECONDS. Bash Date format DD-MM-YYYY. To format date in DD-MM-YYYY format, use the command date +%d-%m-%Y or printf “%(%d-%m-%Y)T\ ” $EPOCHSECONDS. Bash Date format YYYY-MM-DD

How to printf 2015-06-14 in Bash?

The output would be 2015-06-14. Show activity on this post. With recent Bash (version ≥ 4.2), you can use the builtin printf with the format modifier % (strftime_format)T: printf is much faster than date since it’s a Bash builtin while date is an external command.

How to printf faster than date in Bash?

With recent Bash (version ≥ 4.2), you can use the builtin printf with the format modifier % (strftime_format)T: printf is much faster than date since it’s a Bash builtin while date is an external command. As well, printf -v date is faster than date=$ (printf …) since it doesn’t require forking a subshell.