What are Sin Cos tan csc SEC cot called?

What are Sin Cos tan csc SEC cot called?

trigonometry, the branch of mathematics concerned with specific functions of angles and their application to calculations. There are six functions of an angle commonly used in trigonometry. Their names and abbreviations are sine (sin), cosine (cos), tangent (tan), cotangent (cot), secant (sec), and cosecant (csc).

What are the derivatives of the 6 trig functions?

What are the Derivatives of the 6 Trig Functions?

  • Derivation of sin x: (sin x)’ = cos x.
  • Derivative of cos x: (cos x)’ = -sin x.
  • Derivative of tan x: (tan x)’ = sec2 x.
  • Derivative of cot x: (cot x)’ = -cosec2 x.
  • Derivative of sec x: (sec x)’ = sec x. tan x.
  • Derivative of cosec x: (cosec x)’ = -cosec x. cot x.

What is csc SEC and cot used for?

The cosecant is the reciprocal of the sine. The secant is the reciprocal of the cosine. The cotangent is the reciprocal of the tangent.

What is sin cot and csc?

The cotangent of x is defined to be the cosine of x divided by the sine of x: cot x = cos x sin x . The secant of x is 1 divided by the cosine of x: sec x = 1 cos x , and the cosecant of x is defined to be 1 divided by the sine of x: csc x = 1 sin x .

What’s the derivative of csc?

(Math | Calculus | Derivatives | Table Of)

sin x = cos x Proof csc x = -csc x cot x Proof
cos x = – sin x Proof sec x = sec x tan x Proof
tan x = sec2 x Proof cot x = – csc2 x Proof

What is cot csc?

What is the derivative of csc cot?

Math2.org Math Tables: Table of Derivatives

sin x = cos x Proof csc x = -csc x cot x Proof
cos x = – sin x Proof sec x = sec x tan x Proof
tan x = sec2 x Proof cot x = – csc2 x Proof

How to find the derivative of CSC SEC and cot functions?

Derivatives of Csc, Sec and Cot Functions \\displaystyle- { {\\csc}^ {2} {x}} −csc2x. Differentiation Interactive Applet – trigonometric functions. Find the derivative of s = sec (3t + 2). Put `u = 3t + 2`. Then:

What is the derivative of cot X?

The derivative of `cot x` is `-csc^2 x`. Explore animations of these functions with their derivatives here: Differentiation Interactive Applet – trigonometric functions .

How to find the derivative of csc x using quotient rule?

By using the quotient rule and trigonometric identities, we can obtain the following derivatives: `(d(csc x))/(dx)=-csc x cot x`. `(d(sec x))/(dx)=sec x tan x`. `(d(cot x))/(dx)=-csc^2 x`. In words, we would say: The derivative of `csc x` is `-csc x cot x`, The derivative of `sec x` is `sec x tan x` and. The derivative of `cot x` is `-csc^2 x`.

How do you find the derivative of csc x using Bourne’s rule?

by M. Bourne. By using the quotient rule and trigonometric identities, we can obtain the following derivatives: `(d(csc x))/(dx)=-csc x cot x`. `(d(sec x))/(dx)=sec x tan x`. `(d(cot x))/(dx)=-csc^2 x`. In words, we would say: The derivative of `csc x` is `-csc x cot x`,